There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?
A. $$\frac{{6}}{{7}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{3}}{{8}}$$
D. $$\frac{{5}}{{9}}$$
Answer: Option C
Solution(By Examveda Team)
Total cases of checking in the hotels = $${4^3}$$ ways.Cases, when 3 men are checking in different hotels = 4 × 3 × 2 = 24 ways.
Required probability:
$$\eqalign{ & = \frac{{24}}{{{4^3}}} \cr & = \frac{3}{8} \cr} $$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
Join The Discussion