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There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?
Answer & Solution
Correct Answer:
Option
C
Total cases of checking in the hotels = $${4^3}$$ ways.
Cases, when 3 men are checking in different hotels = 4 × 3 × 2 = 24 ways.
Required probability:
$$\eqalign{ & = \frac{{24}}{{{4^3}}} \cr & = \frac{3}{8} \cr} $$
Cases, when 3 men are checking in different hotels = 4 × 3 × 2 = 24 ways.
Required probability:
$$\eqalign{ & = \frac{{24}}{{{4^3}}} \cr & = \frac{3}{8} \cr} $$
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