There is a number consisting of two digits, the digit in the unit's place is twice than digit in the ten's place and if 2 subtracted from the sum of the digits, the difference is equal to $${\frac{1}{6}^{{\text{th}}}}$$ of the number. The number is-

A. 23

B. 25

C. 26

D. 24

Answer: Option D

Solution(By Examveda Team)

Shortcut method:
Do by option
Let the number be 24
Sum of digits = 2 + 4 = 6
⇒ 6 - 2 = $$\frac{1}{6}$$ × 24 = 4 = 4 matched
So, 24 is answer