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There is a number consisting of two digits, the digit in the unit's place is twice than digit in the ten's place and if 2 subtracted from the sum of the digits, the difference is equal to $${\frac{1}{6}^{{\text{th}}}}$$ of the number. The number is-
Answer & Solution
Correct Answer:
Option
D
Shortcut method:
Do by option
Let the number be 24
Sum of digits = 2 + 4 = 6
⇒ 6 - 2 = $$\frac{1}{6}$$ × 24 = 4 = 4 matched
So, 24 is answer
Do by option
Let the number be 24
Sum of digits = 2 + 4 = 6
⇒ 6 - 2 = $$\frac{1}{6}$$ × 24 = 4 = 4 matched
So, 24 is answer
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