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Three numbers are in the ratio 1 : 2 : 3, and the sum of their cubes is 4500. The smallest number will be -
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& x:2x:3x \cr
& {x^3} + 8{x^3} + 27{x^3} = 4500 \cr
& 36{x^3} = 4500 \cr
& {x^3} = \frac{{4500}}{{36}} = 125 \cr
& x = 5 \cr
& {\text{Smallest number is 5}} \cr} $$
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