Three numbers are in the ratio 1 : 2 : 3, and the sum of their cubes is 4500. The smallest number will be -
A. 4
B. 5
C. 6
D. 10
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & x:2x:3x \cr & {x^3} + 8{x^3} + 27{x^3} = 4500 \cr & 36{x^3} = 4500 \cr & {x^3} = \frac{{4500}}{{36}} = 125 \cr & x = 5 \cr & {\text{Smallest number is 5}} \cr} $$Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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