Three numbers which are co-prime to each other are such that the product of the first two is 119 and that of the last two is 391. What is the sum of the three numbers?

A. 47

B. 43

C. 53

D. 51

Answer: Option A

Solution(By Examveda Team)

Since the numbers are co-prime, their HCF = 1
Product of first two numbers = 119
Product of last two numbers = 391
The middle number is common in both of these products.
Hence if we take HCF of 119 and 391, we get the common middle number.
HCF of 119 and 391 = 17
So, Middle Number = 17
First Number = $$\frac{{119}}{{17}}$$ = 7
Last Number = $$\frac{{391}}{{17}}$$ = 23
Sum of the three numbers
= 7 + 17 + 23
= 47