Three unbiased coins are tossed. What is the probability of getting at least 2 heads?
A. $$\frac{1}{4}$$
B. $$\frac{1}{2}$$
C. $$\frac{1}{3}$$
D. $$\frac{1}{8}$$
Answer: Option B
Solution (By Examveda Team)
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}Let E = event of getting at least two heads = {THH, HTH, HHT, HHH}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{4}{8} = \frac{1}{2}$$
This Question Belongs to Arithmetic Ability >> Probability
Join The Discussion