Three unbiased coins are tossed. What is the probability of getting at least 2 heads?

A. $$\frac{1}{4}$$

B. $$\frac{1}{2}$$

C. $$\frac{1}{3}$$

D. $$\frac{1}{8}$$

Answer: Option B

Solution(By Examveda Team)

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at least two heads = {THH, HTH, HHT, HHH}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{4}{8} = \frac{1}{2}$$