Three unbiased coins are tossed. What is the probability of getting at least 2 tails?
A. 0.75
B. 0.5
C. 0.25
D. 0.2
Answer: Option B
Solution(By Examveda Team)
S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}E = {HTT, THT, TTH, TTT}
$$\eqalign{ & {\text{n(S) = 8}} \cr & {\text{n(E) = 4}} \cr & {\text{P(E) = }}\frac{{{\text{n(E)}}}}{{{\text{n(S)}}}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{\text{4}}}{8} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\, = {\text{0}}{\text{.5}} \cr} $$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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