Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3 ?
A. $$\frac{3}{10}$$
B. $$\frac{3}{20}$$
C. $$\frac{2}{5}$$
D. $$\frac{1}{2}$$
Answer: Option A
Solution (By Examveda Team)
Here, S = {1, 2, 3, 4,........, 19, 20}Let E = even of getting a multiple of 3 = {3, 6, 9, 12, 15, 18}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{6}{{20}} = \frac{3}{{10}}$$
This Question Belongs to Arithmetic Ability >> Probability
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