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Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?
Answer & Solution
Correct Answer:
Option
D
Here, S = {1, 2, 3, 4, ....., 19, 20}
Let E = event of getting a multiple of 3 or 5 = {3, 6, 9, 12, 15, 18, 5, 10, 20}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{9}{{20}}$$
Let E = event of getting a multiple of 3 or 5 = {3, 6, 9, 12, 15, 18, 5, 10, 20}
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{9}{{20}}$$
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