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To complete a work, A takes 50% more time than B. If together they take 18 days to complete the work, how much time shall B take to do it?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {\text{We have}} \cr
& {\text{B}} = \frac{3}{2} \times {\text{A}} \cr
& \to {\text{A}} = \frac{2}{3} \times {\text{B}} \cr
& {\text{One day's work,}} \cr
& \Rightarrow {\text{A}} + {\text{B}} = \frac{1}{{18}} \cr
& \Rightarrow \frac{2}{3} \times {\text{B}} + {\text{B}} = \frac{1}{{18}} \cr
& \Rightarrow \frac{5}{3} \times {\text{B}} = \frac{1}{{18}} \cr
& {\text{One}}\,{\text{day's}}\,{\text{work}}\,{\text{of}}\,{\text{B}} \cr
& = \frac{3}{{90}} \cr} $$
B alone can complete the work in
$$\eqalign{ & = \frac{{90}}{3} \cr & = 30\,{\text{days}} \cr} $$
B alone can complete the work in
$$\eqalign{ & = \frac{{90}}{3} \cr & = 30\,{\text{days}} \cr} $$
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LoginLCM=300, then efficiency of A & B is 2,3
total efficiency =5
B alone can complete the work in =18*5/3
=30 day
Then A will take 50% more i.e 150℅ of x days i.e 3/2x days.
So the one day work of A and B together will be
1/x +1/(3/2x) = 1/18
1/x + 2/3x = 1/18
5/3x = 1/18
x = 30
I.e B takes 30 days to complete the work.
Efficiency = 2:3
Efficiency ×day = Total work
Total work =18×5 =90 (2+3=5)
Complite by B = 90÷3= 30 day
So, time taken by A=3x/2 days
ATQ, 2/3x+1/x=1/18
or, 5/3x=1/18
or, x=30
B alone can complete the work in 30 days.
(a+b) 1 day work=1/18
Than b 1 day work portion =3/5*1/18=1/30
B can do --- 1/30 portion in 1 day
Than -------whole or 1 portion in 30 days.(ans)
Effi.of b × Time b = Effi of a+b × Time a+b