?
To do a certain work, A and B work on alternate days, with B beginning the work on the first day. A can finish the work alone in 48 days. If the work gets completed in $$11\frac{1}{3}$$ days, then B alone can finish 4 times the same work in:
Answer & Solution
Correct Answer:
Option
C
Let total work = 48 unit
B × 6 + A × $$\frac{{16}}{3}$$ = 48
B × 6 + 1 × $$\frac{{16}}{3}$$ = 48
B × 6 = $$\frac{{128}}{3}$$
B = $$\frac{{64}}{9}$$
4 × Total work = B × Days
Now, 48 × 4 = $$\frac{{64}}{9}$$ × Days
27 = Days
B × 6 + A × $$\frac{{16}}{3}$$ = 48
B × 6 + 1 × $$\frac{{16}}{3}$$ = 48
B × 6 = $$\frac{{128}}{3}$$
B = $$\frac{{64}}{9}$$
4 × Total work = B × Days
Now, 48 × 4 = $$\frac{{64}}{9}$$ × Days
27 = Days
Join the Discussion
Login to post a comment or share your explanation.
Login