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Calculus
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To evaluate the double integral \[\int_0^8 {\left( {\int_{\frac{{\text{y}}}{2}}^{\frac{{\text{y}}}{2} + 1} {\left( {\frac{{2{\text{x}} - {\text{y}}}}{2}} \right){\text{dx}}} } \right){\text{dy,}}} \]      we make the substitution \[{\text{u}} = \frac{{2{\text{x}} - {\text{y}}}}{2}\]   and \[{\text{v}} = \frac{{\text{y}}}{2}.\]  The integral will reduce to

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Correct Answer: Option B
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