Total pressure on a 1 m × 1 m gate immersed vertically at a depth of 2 m below the free water surface will be
A. 1000 kg
B. 4000 kg
C. 2000 kg
D. 8000 kg
Answer: Option A
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In this question there must be figure b/c of the name of gate lmxml..
W*A*X = 9.81 *1000*(1*1)*1 because x is nothing but center of gravity from free surface. When we talk about value of total pre. then we have to take X as distance of C.G. from free surface.
since 2m vertically downward from free surface.
therefore COG from free surface equal to (2+1/2)=2.5m
using formula for
pressure = W*A*X
= (9.81*1000) * (1*1)*2.5 N
= 2500 kg (answer)
(1Kgf=9.81N)
since 2m vertically downward from free surface.
therefore COG from free surface equal to (2+1/2)=2.5m
using formula for
pressure = W*A*X
= (9.81*1000) * (1*1)*2.5 N
= 2500 kg (answer)
(1Kgf=9.81N)