Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is = ?
A. 14 : 25
B. 10 : 21
C. 12 : 23
D. 13 : 22
Answer: Option D
Solution (By Examveda Team)
According to the question,| Sn | : | Fe |
| A → 1 | : | 2 = 3) × 5 |
| B → 2 | : | 3 = 5) × 3 |
| Sn | : | Fe |
| A → 5 | : | 10 = 15) × 3 |
| B → 6 | : | 9 = 15) × 4 |
| Sn | : | Fe |
| A →15 | : | 30 |
| B →24 | : | 36 |
| 39 | : | 66 |
= 39 : 66
= 13 : 22
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Comments (1)
Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10

here the first the total quantities are made equal and then it is distributed in the specicified ratio