Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is = ?
A. 14 : 25
B. 10 : 21
C. 12 : 23
D. 13 : 22
Answer: Option D
Solution(By Examveda Team)
According to the question,Sn | : | Fe |
A → 1 | : | 2 = 3) × 5 |
B → 2 | : | 3 = 5) × 3 |
Sn | : | Fe |
A → 5 | : | 10 = 15) × 3 |
B → 6 | : | 9 = 15) × 4 |
Sn | : | Fe |
A →15 | : | 30 |
B →24 | : | 36 |
39 | : | 66 |
= 39 : 66
= 13 : 22
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Comments ( 1 )
Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
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D. 9 : 8 : 10
here the first the total quantities are made equal and then it is distributed in the specicified ratio