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Two alloys contain tin and iron in the ratio of 1...

This question belongs to Arithmetic Ability Ratio
Ratio
?

Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is = ?

Answer & Solution
Correct Answer: Option D
According to the question,
Sn  :  Fe
A → 1 : 2 = 3) × 5
B → 2 : 3 = 5) × 3
Making quantity equal
Sn  :  Fe
A → 5 : 10 = 15) × 3
B → 6 : 9 = 15) × 4

Sn  :  Fe
A →15 : 30
B →24 : 36
39 : 66
In final mixture Sn : Fe
= 39 : 66
= 13 : 22
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1 Comment
Vasanth Jadav
Vasanth Jadav 5 years ago
here the first the total quantities are made equal and then it is distributed in the specicified ratio
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