Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is = ?

A. 14 : 25

B. 10 : 21

C. 12 : 23

D. 13 : 22

Answer: Option D

Solution(By Examveda Team)

According to the question,

Sn	:	Fe
A → 1	:	2 = 3) × 5
B → 2	:	3 = 5) × 3

Making quantity equal

Sn	:	Fe
A → 5	:	10 = 15) × 3
B → 6	:	9 = 15) × 4

Sn	:	Fe
A →15	:	30
B →24	:	36
39	:	66

In final mixture Sn : Fe
= 39 : 66
= 13 : 22