Two brother X and Y appeared for an exam. Let A be the event that X is selected and B is the event that Y is selected.
The probability of A is $$\frac{{1}}{{7}}$$ and that of B is $$\frac{{2}}{{9}}$$. Find the probability that both of them are selected.
A. $$\frac{{1}}{{63}}$$
B. $$\frac{{2}}{{35}}$$
C. $$\frac{{2}}{{63}}$$
D. $$\frac{{9}}{{14}}$$
Answer: Option C
Solution (By Examveda Team)
Given, A be the event that X is selected and B is the event that Y is selected.$$P(A) = \frac{1}{7},\,P(B) = \frac{2}{9}$$
Let C be the event that both are selected.
P(C) = P(A) × P(B) as A and B are independent events:
$$\eqalign{ & = \left( {\frac{1}{7}} \right) \times \left( {\frac{2}{9}} \right) \cr & = \frac{2}{{63}} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
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