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Two cards are drawn from a pack of well shuffled cards. Find the probability that one is a club and other in King.

A. $$\frac{{1}}{{13}}$$

B. $$\frac{{4}}{{13}}$$

C. $$\frac{{1}}{{52}}$$

D. $$\frac{{1}}{{26}}$$

Answer: Option D

Solution(By Examveda Team)

Let X be the event that cards are in a club which is not king and other is the king of club.
Let Y be the event that one is any club card and other is a non-club king.
Hence, required probability:
$$\eqalign{ & = P(A) + P(B) \cr & = \frac{{^{12}{C_1}{ \times ^1}{C_1}}}{{^{52}{C_2}}} + \frac{{^{13}{C_1}{ \times ^3}{C_1}}}{{^{52}{C_2}}} \cr & = \left( {\frac{{2 \times \left( {12 \times 1} \right)}}{{52 \times 51}}} \right) + \left( {\frac{{2\left( {13 \times 3} \right)}}{{52 \times 51}}} \right) \cr & = \left( {\frac{{24 + 78}}{{52 \times 51}}} \right) \cr & = \frac{1}{{26}} \cr} $$

This Question Belongs to Arithmetic Ability >> Probability

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