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Strength of Materials in ME
?

Two closely-coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is double that of spring 'B'. The stiffness of spring 'A' will be __________ that of spring 'B'.

Answer & Solution
Correct Answer: Option D
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1 Comment
Atif Muneer
Atif Muneer 5 years ago
K= GD⁴/64R³×n
where D = Mean diameter of the spring coil, d = Diameter of the spring wire, n = Number of active coils, G = Modulus of rigidity for the spring material, W = Axial load on the spring.

From here it is clear that,

k ∝ d4