Two copper conductors have equal length. The cross-sectional area of one conductor is four times that of the other. If the conductor having smaller cross-sectional area has a resistance of 40 ohms the resistance of other conductor will be
A. 160 ohms
B. 80 ohms
C. 20 ohms
D. 10 ohms
Answer: Option D
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If Area A1 is =4a1 and Area A2 is =a2/4. Then Rt=40/4=10 ohms
R= rhol/A
then 40/4 = 10 ohms