Two dice are thrown simultaneously. Find the probability of getting a multiple of 2 on one dice and multiple of 3 on the other dice.

A. $$\frac{{5}}{{12}}$$

B. $$\frac{{11}}{{36}}$$

C. $$\frac{{5}}{{36}}$$

D. $$\frac{{13}}{{36}}$$

Answer: Option B

Solution(By Examveda Team)

Let X be required events and S be the sample space
then X = {(2, 3), (2, 6), (4, 3), (4, 6), (6, 3), (6, 6), (3, 2), (6, 2), (3, 4), (6, 4), (3, 6)}
n(X) = 11, n(S) = 36
Hence, required probability
$$\eqalign{ & = \frac{{n(X)}}{{n(S)}} \cr & = \frac{{11}}{{36}} \cr} $$