Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at most 5?
A. $$\frac{{2}}{{9}}$$
B. $$\frac{{2}}{{18}}$$
C. $$\frac{{4}}{{9}}$$
D. $$\frac{{5}}{{18}}$$
Answer: Option D
Solution(By Examveda Team)
In a simultaneous throw of two dice, we have n(s) = 6 × 6 = 36Let E = event of getting two numbers whose sum is at most 5
Then E = {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}
therefore, n(E) = 10
And p(E) = p( getting two numbers whose sum is at most 5)
$$\eqalign{ & {\text{p}}\left( {\text{E}} \right) = \frac{{{\text{n}}\left( {\text{E}} \right)}}{{{\text{n}}\left( {\text{S}} \right)}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{10}}{{36}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{5}{{18}} \cr} $$
Hence the answer is $$\frac{{5}}{{18}}$$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
Join The Discussion