Two friends A and B apply for a job in the same company. The chances of A getting selected is $$\frac{{2}}{{5}}$$ and that of B is $$\frac{{4}}{{7}}$$. What is the probability that both of them get selected?
A. $$\frac{{8}}{{35}}$$
B. $$\frac{{34}}{{35}}$$
C. $$\frac{{27}}{{35}}$$
D. None of these
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & P\left( A \right) = \frac{2}{5} \cr & P\left( B \right) = \frac{4}{7} \cr} $$E = {A and B both get selected}
$$\eqalign{ & P\left( E \right) = {\text{ }}P\left( A \right) \times P\left( B \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{2}{5} \times \frac{4}{7} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{8}{{35}} \cr} $$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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