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This question belongs to Arithmetic Ability Ratio
Ratio
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Two glasses of equal volume respectively are half and three - fourths filled with milk. They are then filled to brim by adding water. Their contents are then poured into another vessel. What will be the ratio of milk to water in this vessel ?

Answer & Solution
Correct Answer: Option D
$$\eqalign{ & {\text{Milk in 1st glass}} \cr & = \frac{1}{2}{\text{ unit}} \cr & {\text{Milk in 2nd glass}} \cr & = \frac{3}{4}{\text{ unit}} \cr & {\text{Water in 1st glass}} \cr & = \frac{1}{2}{\text{ unit}} \cr & {\text{Water in 2nd glass}} \cr & = \frac{1}{4}{\text{ unit}}{\text{}} \cr & \therefore {\text{Required ratio}} \cr & = \frac{{\frac{1}{2} + \frac{3}{4}}}{{\frac{1}{2} + \frac{1}{4}}} \cr & = \frac{5}{4} \times \frac{4}{3} \cr & = 5:3 \cr} $$
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