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Two persons having different productivity of labour, working together can reap a field in 2 days. If one-third of the field was reaped by the first man and rest by the other one working alternatively took 4 days. How long did it take for the faster person to reap the whole field working alone?

A. 3

B. 6

C. 8

D. 12

E. None of these

Answer: Option A

Solution(By Examveda Team)

Total efficiency of two persons = 50% [As they complete work in 2 days. ]
First Person completes work = $$\frac{1}{3}$$ = 33.33% [In 2 days]
Rest work will be completed by Second man = $$\frac{2}{3}$$ = 66.66% [In 2 days]
So, efficiency of second person is greater.
Efficiency of second person = $$\frac{{66.66}}{2}$$  = 33.33% per day
Then, Second person will complete whole work in,
= $$\frac{{100}}{{33.33}}$$  = 3 days.

This Question Belongs to Arithmetic Ability >> Time And Work

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Comments ( 2 )

  1. Md Mahabubor
    Md Mahabubor :
    5 years ago

    A=1/3
    B=2/3
    23 part is completed 4days
    Then whole by 2nd man = 3/2*4=6
    First man's part= 1/2-1/6=1/3
    Answer : 3day

  2. Md Ibrahim
    Md Ibrahim :
    6 years ago

    1/3---4=12 days
    1-1/3=2/3---4=6 days
    1/6----1 day
    1/2----6/2=3 days.

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