Two persons having different productivity of labour, working together can reap a field in 2 days. If one-third of the field was reaped by the first man and rest by the other one working alternatively took 4 days. How long did it take for the faster person to reap the whole field working alone?
A. 3
B. 6
C. 8
D. 12
E. None of these
Answer: Option A
Solution(By Examveda Team)
Total efficiency of two persons = 50% [As they complete work in 2 days. ]First Person completes work = $$\frac{1}{3}$$ = 33.33% [In 2 days] Rest work will be completed by Second man = $$\frac{2}{3}$$ = 66.66% [In 2 days] So, efficiency of second person is greater. Efficiency of second person = $$\frac{{66.66}}{2}$$ = 33.33% per day Then, Second person will complete whole work in, = $$\frac{{100}}{{33.33}}$$ = 3 days.
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Comments ( 2 )
Related Questions on Time and Work
A. 18 days
B. 24 days
C. 30 days
D. 40 days
A=1/3
B=2/3
23 part is completed 4days
Then whole by 2nd man = 3/2*4=6
First man's part= 1/2-1/6=1/3
Answer : 3day
1/3---4=12 days
1-1/3=2/3---4=6 days
1/6----1 day
1/2----6/2=3 days.