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This question belongs to Arithmetic Ability Time And Work
Time and Work
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Two pipes A and B can fill a tank in 36 min. and 45 min. respectively. Another pipe C can empty the tank in 30 min. First A and B are opened. After 7 minutes, C is also opened. The tank filled up in:

Answer & Solution
Correct Answer: Option B
Pipe A can fill empty tank in 36 min.
Pipe A can fill the tank = $$\frac{{100}}{{36}}$$ = 2.77% per minute
Pipe B can fill empty tank in 45 min.
Pipe B can fill the tank = $$\frac{{100}}{{45}}$$ = 2.22% per min.
A and B can together fill the tank
= (2.77 + 2.22) ≈ 5% per minute
So, A and B can fill the tank in 7 min.
= 7 × 5 = 35% of the tank
Rest tank to be filled = 100 - 35 = 65%
C can empty the full tank in 30 min.
C can empty the tank = $$\frac{{100}}{{30}}$$ = 3.33% per min.
C is doing negative work i.e. emptying the tank
A, B and C can together fill the tank,
= 2.77% + 2.22% - 3.33% = 1.67% tank per minute
So, A, B and C will take time to fill 65% empty tank,
= $$\frac{{65}}{{1.67}}$$ = 39 min. (Approx)
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6 Comments
Hrithik Fan
Hrithik Fan 5 years ago
46 full krne k liye lgega...39 empty k liye
নুরুন নবী
নুরুন নবী 8 years ago
I'm also getting 46 as the answer. Which one is the correct?
Goutam Chandra
Goutam Chandra 10 years ago
39+7=46 answer is right
Manoj Kumar
Manoj Kumar 10 years ago
A efficiency 5
B efficiency 4
c efficiency 6
work= efficiency à time
5Ã36=180
4Ã45=180
6Ã30=180
so
work=180
then A&B 7min work is
180-7Ã(5+4)
180-7Ã9
=117
then now c also open
so efficiency is 5+4-6=3
so tnk fll up in
=117÷3
=39 min
Abhimanyu Kataria
Abhimanyu Kataria 10 years ago
46 minutes total time 39 +7
Seshu
Seshu 11 years ago
and b 's work in 1 min 1/20andso a and b for 7 min 7/20,then remaining work is 13/20, after 7 min a+b+c 's work is 1/60 in 1 min and so for 13/20 th work done in 39 min and add before 7 min finally getting 46 min.