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Two pipes can fill an empty tank separately in 24 minutes and 40 minutes respectively and a third pipe can empty 30 gallons of water per minute. If all three pipes are open, empty tanks become full in one hour. The capacity of the tank (in gallons) is:

A. 800 gallons

B. 600 gallons

C. 500 gallons

D. 400 gallons

Answer: Option B

Solution(By Examveda Team)

Let capacity of the tank = x gallons;
Part of the tank filled in 1 minute
$$\eqalign{ & = {\frac{x}{{24}}} + {\frac{x}{{40}}} - 30 \cr & {\text{Or}}, {\frac{x}{{24}}} + {\frac{x}{{40}}} - 30 = \frac{x}{{60}} \cr & {\text{Or}}, \frac{x}{{24}} + \frac{x}{{40}} - \frac{x}{{60}} = 30 \cr & {\text{Or}}, {\frac{{ {10x + 6x - 4x} }}{{240}}} = 30 \cr & {\text{Or}},\,12x = 30 \times 240 \cr & {\text{Or}},\,x = 600\,{\text{gallons}} \cr} $$

This Question Belongs to Arithmetic Ability >> Time And Work

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Comments ( 2 )

  1. Rahul
    Rahul :
    3 years ago

    Work done by two pipes individually is 241​ and 401​ respectively
    work done by all three pipe together is 601​
    Work done by third pipe to empty tha tank =601​−(241​+401​)
    =601​−1208​
    =−201​ [-ve sign means emptying]
    ∴ Volume of 201​ part =30 gallons
    ∴ Volume of whole tank =30×20=600 gallons
    Answer is 600 gallons.

  2. Munna Dey
    Munna Dey :
    3 years ago

    How to find x/60?

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