Two pipes can fill an empty tank separately in 24 minutes and 40 minutes respectively and a third pipe can empty 30 gallons of water per minute. If all three pipes are open, empty tanks become full in one hour. The capacity of the tank (in gallons) is:
A. 800 gallons
B. 600 gallons
C. 500 gallons
D. 400 gallons
Answer: Option B
Solution(By Examveda Team)
Let capacity of the tank = x gallons; Part of the tank filled in 1 minute$$\eqalign{ & = {\frac{x}{{24}}} + {\frac{x}{{40}}} - 30 \cr & {\text{Or}}, {\frac{x}{{24}}} + {\frac{x}{{40}}} - 30 = \frac{x}{{60}} \cr & {\text{Or}}, \frac{x}{{24}} + \frac{x}{{40}} - \frac{x}{{60}} = 30 \cr & {\text{Or}}, {\frac{{ {10x + 6x - 4x} }}{{240}}} = 30 \cr & {\text{Or}},\,12x = 30 \times 240 \cr & {\text{Or}},\,x = 600\,{\text{gallons}} \cr} $$
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Related Questions on Time and Work
A. 18 days
B. 24 days
C. 30 days
D. 40 days
Work done by two pipes individually is 241 and 401 respectively
work done by all three pipe together is 601
Work done by third pipe to empty tha tank =601−(241+401)
=601−1208
=−201 [-ve sign means emptying]
∴ Volume of 201 part =30 gallons
∴ Volume of whole tank =30×20=600 gallons
Answer is 600 gallons.
How to find x/60?