Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
A. 39, 30
B. 41, 32
C. 42, 33
D. 43, 34
E. None of these
Answer: Option C
Solution(By Examveda Team)
Let their marks be (x + 9) and xThen,
$$\eqalign{ & x + 9 = \frac{{56}}{{100}}\left( {x + 9 + x} \right) \cr & \Rightarrow 25\left( {x + 9} \right) = 14\left( {2x + 9} \right) \cr & \Rightarrow 3x = 99 \cr & \Rightarrow x = 33 \cr} $$
So, their marks are 42 and 33
Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
Join The Discussion