Two teams Arrogant and Overconfident are participating in a cricket tournament. The odds that team Arrogant will be champion is 5 to 3, and the odds that team Overconfident will be the champion is 1 to 4. What are the odds that either Arrogant or team Overconfident will become the champion?
A. 3 to 2
B. 5 to 2
C. 6 to 1
D. 33 to 7
Answer: Option D
Solution(By Examveda Team)
As probability of a both the teams (Arrogant and Overconfident) winning simultaneously is zero.$$\eqalign{ & P\left( {A \cap O} \right) = 0 \cr & P\left( {A \cap B} \right) = P\left( A \right) + P\left( B \right) \cr & = \frac{5}{8} + \frac{1}{5} \cr & = \frac{{33}}{{40}} \cr} $$
So required odds will be 33 : 7
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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