Two unbiased coins are tossed. What is probability of getting at most one tail ?
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{3}}$$
C. $$\frac{{3}}{{2}}$$
D. $$\frac{{3}}{{4}}$$
Answer: Option D
Solution(By Examveda Team)
Total 4 cases = [HH, TT, TH, HT]Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability = $$\frac{{3}}{{4}}$$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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