Two unbiased coins are tossed. What is probability of getting at most one tail ?
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{3}}$$
C. $$\frac{{3}}{{2}}$$
D. $$\frac{{3}}{{4}}$$
Answer: Option D
Solution (By Examveda Team)
Total 4 cases = [HH, TT, TH, HT]Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability = $$\frac{{3}}{{4}}$$
This Question Belongs to Arithmetic Ability >> Probability
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