Two vessels A and B contain milk 8 : 5 and 5 : 2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing $$69\frac{3}{{13}}$$ % milk is =?
A. 3 : 5
B. 5 : 2
C. 5 : 7
D. 2 :7
Answer: Option D
Solution(By Examveda Team)
Milk in 1 litre mix. in A = $$\frac{8}{{13}}$$Milk in 1 litre mix. in B = $$\frac{5}{{7}}$$
Milk in 1 litre of final mix. = $$\frac{{900}}{{13}} \times \frac{1}{{100}} \times 1 = \frac{9}{{13}}$$
By the rule of alligation, we have :
∴ Required ratio $$ = \frac{2}{{91}} : \frac{1}{{13}} = 2 : 7$$
Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
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