Water is continuously supplied from a reservoir to a locality at the steady rate of 10000 liters per hours. When delivery exceeds demand the excess water is stored in a tank. If the demand for 8 consecutive three hour periods is 10000, 10000, 45000, 25000, 40000, 15000, 60000 and 35000 liters respectively, what will be the minimum capacity required of the water tank (in thousand liters)to meet the demand and avoid any wastage?
A. 10
B. 30
C. 40
D. 50
Answer: Option C
Solution(By Examveda Team)
We have the following table:| Period | Supply | Demand | Calculation | Excess Qty. in tank |
| 0 - 3 hrs | 30000 | 10000 | 30000 - 10000 | 20000 |
| 3 - 6 hrs | 30000 | 10000 | 20000 + 30000 - 10000 | 40000 |
| 6 - 9 hrs | 30000 | 45000 | 40000 + 30000 - 45000 | 25000 |
| 9 - 12 hrs | 30000 | 25000 | 25000 + 30000 - 25000 | 30000 |
| 12 - 15 hrs | 30000 | 40000 | 30000 + 30000 - 40000 | 20000 |
| 15 - 18 hrs | 30000 | 15000 | 20000 + 30000 - 15000 | 35000 |
| 18 - 21 hrs | 30000 | 60000 | 35000 + 30000 - 60000 | 5000 |
| 21 - 24 hrs | 30000 | 35000 | 5000 + 30000 - 35000 | 0 |
Which is the required minimum capacity to avoid wastage.
This Question Belongs to Arithmetic Ability >> Pipes And Cistern
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