What is $$\sin \alpha - \sin \beta = ?$$
A. $$2\cos \frac{{\alpha + \beta }}{2}\sin \frac{{\alpha - \beta }}{2}$$
B. $$2\sin \frac{{\alpha + \beta }}{2}\sin \frac{{\alpha - \beta }}{2}$$
C. $$2\cos \frac{{\alpha - \beta }}{2}\sin \frac{{\alpha + \beta }}{2}$$
D. $$2\cos \frac{{\alpha + \beta }}{2}\cos \frac{{\alpha - \beta }}{2}$$
Answer: Option A
Solution (By Examveda Team)
$$\sin \alpha - \sin \beta = 2\cos \frac{{\alpha + \beta }}{2}.\sin \frac{{\alpha - \beta }}{2}$$This Question Belongs to Arithmetic Ability >> Trigonometry
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