What is the approximate filament resistance of a light bulb if it operates from a 110 V source and 0.6 A of current is flowing?
A. 183 Ω
B. 18.3 Ω
C. 66 Ω
D. 6.6 Ω
Answer: Option A
Solution (By Examveda Team)
This question is about Ohm's Law, which is a fundamental rule in electrical circuits.Ohm's Law tells us how Voltage (V), Current (I), and Resistance (R) are related.
The formula for Ohm's Law is: V = I * R
Where:
* V is the Voltage (measured in Volts)
* I is the Current (measured in Amperes or Amps)
* R is the Resistance (measured in Ohms)
In our question, we know:
* The Voltage (V) is 110 V
* The Current (I) is 0.6 A
We need to find the Resistance (R).
To find R, we can rearrange the formula: R = V / I
Now, let's plug in the values:
R = 110 V / 0.6 A
R ≈ 183.33 Ω
So, the closest answer from the options is 183 Ω.
That means Option A is correct.
This Question Belongs to Electrical Engineering >> Ohms Law
according to ohms law I = V/R so here given voltage V= 110 v, current I = 0.6 A Therefore R = V/I = 110/0.6= 183.3 ohm
To find the filament resistance of the light bulb, we can use Ohm's Law, which states:
[
R = frac{V}{I}
]
Where:
- ( R ) is the resistance,
- ( V ) is the voltage,
- ( I ) is the current.
### Given:
- ( V = 110 , V )
- ( I = 0.6 , A )
### Step 1: Calculate the resistance:
[
R = frac{110 , V}{0.6 , A} = frac{110}{0.6} approx 183.33 , Omega
]
### Conclusion:
Thus, the approximate filament resistance of the light bulb is:
**A. 183 Ω.**
How it is?
How it is..??
Kaskay