Directions (1 - 5): Study the table carefully to answer the questions that follow:
Number of Boys and Girls (in Hundreds) in six different Years in 5 different Schools.
| School → | A | B | C | D | E | |||||
| Year ↓ | Boys | Girls | Boys | Girls | Boys | Girls | Boys | Girls | Boys | Girls |
| 2005 | 3.3 | 3.6 | 5.2 | 3.1 | 5.5 | 4.5 | 2.4 | 1.4 | 6.5 | 6.6 |
| 2006 | 6.6 | 4.2 | 4.9 | 2.2 | 6.9 | 3.3 | 4.4 | 2.3 | 5.5 | 3.6 |
| 2007 | 9.3 | 6.9 | 4.7 | 4.2 | 5.8 | 4.9 | 6.4 | 3.3 | 2.7 | 2.4 |
| 2008 | 5.4 | 9.6 | 6.3 | 5.4 | 6.6 | 5.2 | 5.3 | 5.4 | 5.4 | 5.7 |
| 2009 | 8.4 | 12.9 | 7.5 | 5.9 | 8.7 | 6.6 | 12.1 | 5.2 | 6.8 | 6.5 |
| 2010 | 12.3 | 14.4 | 9.8 | 4.4 | 11.7 | 4.2 | 12.2 | 9.4 | 10.8 | 12.7 |
What is the approximate percentage decrease in the number of boys in School D in the year 2008 as compared to that in the previous year ?
A. 17%
B. 12%
C. 9%
D. 5%
E. 23%
Answer: Option A
Solution (By Examveda Team)
Number of boys in School D in 2007= 6.4 × 100
= 640
Number of boys in School D in 2008
= 5.3 ×100
= 530
$$\eqalign{ & \text{Decrease }\% \cr & = \left(\frac{110}{640}\times100\right)\% \cr & = \frac{275}{16}\% \cr & = 17.1\% \cr & \approx 17\% \cr} $$
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