What is the expected output?
class Animal {
Animal() {
System.out.println("Animal");
}
}
class Wild extends Animal{
Wild() {
System.out.println("Wild");
super();
}
}
public class Test {
public static void main(String args[]) {
Wild wild = new Wild();
}
}
class Animal {
Animal() {
System.out.println("Animal");
}
}
class Wild extends Animal{
Wild() {
System.out.println("Wild");
super();
}
}
public class Test {
public static void main(String args[]) {
Wild wild = new Wild();
}
}A. Animal Wild
B. Wild Animal
C. Runtime Exception
D. Compilation Error
Answer: Option D
Solution(By Examveda Team)
super() call must be the first statement in a constructor.
This Question Belongs to Java Program >> Constructors And Methods
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Comments ( 1 )
What is a constructor in Java?
A. A special method to create instances of classes
B. A method used for mathematical calculations
C. A method to perform string manipulations
D. An exception handling mechanism
In Java, which method is automatically called when an object is created?
A. start()
B. main()
C. init()
D. constructor()
What is method overloading in Java?
A. Defining multiple methods with the same name in the same class
B. Calling methods from another class
C. Using methods to load data from a file
D. Running methods in parallel threads
super() must be the first statement in a constructor if written manually by the user because whenever we call base class it has to initialize all the members of the super class or initialise the superclass object as it is being inherited by the base class