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What is the greatest number of 3 digits which when divided by 6, 9 and 12 leaves a remainder of 3 in each case ?

A. 903

B. 939

C. 975

D. 996

Answer: Option C

Solution(By Examveda Team)

Greatest number of three digits is 999. LCM of 6, 9 and 12 is 36
On dividing 999 by 36, the remainder obtained is 27.
So, required number = (999 - 27) + 3 = 975

This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M

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