What is the greatest number of 3 digits which when divided by 6, 9 and 12 leaves a remainder of 3 in each case ?
A. 903
B. 939
C. 975
D. 996
Answer: Option C
Solution(By Examveda Team)
Greatest number of three digits is 999. LCM of 6, 9 and 12 is 36On dividing 999 by 36, the remainder obtained is 27.
So, required number = (999 - 27) + 3 = 975
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