What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?
A. 1108
B. 1683
C. 2007
D. 3363
Answer: Option B
Solution(By Examveda Team)
LCM of 5, 6, 7 and 8 = 840 Hence the number can be written in the form (840k + 3) which is divisible by 9 If k = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9 If k = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9 Hence, 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainderJoin The Discussion
Comments ( 1 )
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
850k+3, why you added 3 in this