What is the output for the below code?
public class Test{
int _$;
int $7;
int do;
public static void main(String argv[]){
Test test = new Test();
test.$7=7;
test.do=9;
System.out.println(test.$7);
System.out.println(test.do);
System.out.println(test._$);
}
}
public class Test{
int _$;
int $7;
int do;
public static void main(String argv[]){
Test test = new Test();
test.$7=7;
test.do=9;
System.out.println(test.$7);
System.out.println(test.do);
System.out.println(test._$);
}
}A. 7 9 0
B. 7 0 0
C. Compile error - $7 is not valid identifier.
D. Compile error - do is not valid identifier.
E. None of these
Answer: Option D
Solution (By Examveda Team)
$7 is valid identifier. Identifiers must start with a letter, a currency character ($), or underscore ( _ ). Identifiers cannot start with a number. You can't use a Java keyword as an identifier. do is a Java keyword.
This Question Belongs to Java Program >> Data Types And Variables
Related Questions on Data Types and Variables
Which of the following is not a valid identifier for a Java variable?
A. my_var
B. _myVar
C. 3rdVar
D. $var
Join The Discussion