What is the possibility of having 53 Thursdays in a non-leap year?
A. $$\frac{{6}}{{7}}$$
B. $$\frac{{1}}{{365}}$$
C. $$\frac{{1}}{{7}}$$
D. $$\frac{{53}}{{365}}$$
Answer: Option C
Solution(By Examveda Team)
A non-leap year has 365 days, which has 52 weeks (364 days) means 52 ThursdaysThus there is just 1 day extra
We want it to be Thursday
Total possibilities are 7 (Sunday to Saturday means 7 days)
∴ Probability of 53 Thursday = $$\frac{{1}}{{7}}$$
This Question Belongs to Arithmetic Ability >> Probability
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