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What is the probability of getting a sum 9 from two throws of a dice ?
Answer & Solution
Correct Answer:
Option
C
In two throws of dice, n(S) = (6 × 6) = 36
Let E = event of getting a sum 9 = [(3, 6), (4, 5), (5, 4), (6, 3)]
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{4}{{36}} = \frac{1}{9}$$
Let E = event of getting a sum 9 = [(3, 6), (4, 5), (5, 4), (6, 3)]
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{4}{{36}} = \frac{1}{9}$$
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