What is the probability that a number selected from numbers 1, 2, 3, ......, 30, is prime number, when each of the given numbers is equally likely to be selected?
A. $$\frac{{9}}{{30}}$$
B. $$\frac{{8}}{{30}}$$
C. $$\frac{{10}}{{30}}$$
D. $$\frac{{11}}{{30}}$$
Answer: Option C
Solution (By Examveda Team)
X = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29}n(X) = 10, n(S) = 30
Hence required probability,
$$\eqalign{ & = \frac{{n(X)}}{{n(S)}} \cr & = \frac{{10}}{{30}} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
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