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What is the probability that a number selected from numbers 1, 2, 3, ......, 30, is prime number, when each of the given numbers is equally likely to be selected?
Answer & Solution
Correct Answer:
Option
C
X = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29}
n(X) = 10, n(S) = 30
Hence required probability,
$$\eqalign{ & = \frac{{n(X)}}{{n(S)}} \cr & = \frac{{10}}{{30}} \cr} $$
n(X) = 10, n(S) = 30
Hence required probability,
$$\eqalign{ & = \frac{{n(X)}}{{n(S)}} \cr & = \frac{{10}}{{30}} \cr} $$
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