What is the probability that a number selected from numbers 1, 2, 3, ......, 30, is prime number, when each of the given numbers is equally likely to be selected?

A. $$\frac{{9}}{{30}}$$

B. $$\frac{{8}}{{30}}$$

C. $$\frac{{10}}{{30}}$$

D. $$\frac{{11}}{{30}}$$

Answer: Option C

Solution(By Examveda Team)

X = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29}
n(X) = 10, n(S) = 30
Hence required probability,
$$\eqalign{ & = \frac{{n(X)}}{{n(S)}} \cr & = \frac{{10}}{{30}} \cr} $$