Directions (1 - 5): Study the following table carefully and answer the questions given below:
Number (N) of Candidates (In lakhs) Appearing for An Entrance Examination from six different States and The percentage (P) of candidates clearing the Same over the years.
STATE → | A | B | C | D | E | F | ||||||
YEAR ↓ | N | P | N | P | N | P | N | P | N | P | N | P |
2004 | 1.23 | 42 | 1.04 | 51 | 1.11 | 32 | 1.32 | 24 | 1.23 | 36 | 1.33 | 31 |
2005 | 1.05 | 43 | 1.12 | 62 | 1.07 | 47 | 1.15 | 49 | 1.18 | 55 | 1.24 | 24 |
2006 | 2.04 | 38 | 1.48 | 32 | 1.08 | 28 | 1.96 | 35 | 1.42 | 49 | 1.58 | 26 |
2007 | 1.98 | 41 | 2.07 | 43 | 1.19 | 30 | 1.88 | 46 | 1.36 | 47 | 1.79 | 29 |
2008 | 1.66 | 53 | 1.81 | 50 | 1.56 | 42 | 1.83 | 60 | 1.73 | 57 | 1.86 | 34 |
2009 | 1.57 | 39 | 1.73 | 36 | 1.64 | 52 | 2.01 | 56 | 1.69 | 55 | 1.95 | 37 |
What is the ratio of the total number of candidates clearing the entrance examination from state B in the year 2004 to that of those clearing the entrance examination from State C in the same year?
A. 221 : 148
B. 218 : 143
C. 148 : 221
D. 143 : 218
E. None of these
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & \text{Required ratio} \cr & = \frac{1.04\text{ lakhs}\times51\%}{1.11\text{ lakhs}\times32\%} \cr & = \frac{1.04\times51}{1.11\times32} \cr & = \frac{104\times51}{111\times32} \cr & = \frac{13\times17}{37\times4} \cr & = \frac{221}{148} \cr & = 221:148 \cr} $$Related Questions on Table Chart
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