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What is the ratio whose terms differ by 40 and the measure of which is $$\frac{2}{7}$$ ?

A. 6 : 56

B. 14 : 56

C. 16 : 56

D. 16 : 72

Answer: Option C

Solution(By Examveda Team)

Let the terms of the ratio be x and x + 40
$$\eqalign{ & {\text{Then,}} \cr & = \frac{x}{{x + 40}} = \frac{2}{7} \cr & \Rightarrow 7x = 2x + 80 \cr & \Rightarrow 5x = 80 \cr & \Rightarrow x = 16 \cr & \therefore {\text{Required ratio}} \cr & = 16:56 \cr} $$

This Question Belongs to Arithmetic Ability >> Ratio

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