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What is the sum of all two digit numbers that gives a remainder of 3 when they are divided by 7?

A. 666

B. 676

C. 683

D. 777

Answer: Option B

Solution(By Examveda Team)

The two digit number which gives a remainder of 3 when divided by 7 are:
10, 17, 24 ..... 94.
Now, these number are in AP series with
1st Term, a = 10;
Number of Terms, n = 13;
Last term, L = 94 and
Common Difference, d = 7.
Sum,
$$\eqalign{ & = \left\{ {{\text{n}} \times \frac{{{\text{a}} + {\text{L}}}}{2}} \right\} \cr & = 13 \times 52 \cr & = 676 \cr} $$

This Question Belongs to Arithmetic Ability >> Number System

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Comments ( 4 )

  1. Sajjad Hyder112
    Sajjad Hyder112 :
    1 year ago

    Mozahid Mallika we are taking n 13 because 7÷(91) is 13 and 3 is reminder

  2. Sajjad Hyder112
    Sajjad Hyder112 :
    1 year ago

    Mozahid Mallika we are taking n 13 because 7÷(91) is 13 and 3 is reminder

  3. Trc Boys
    Trc Boys :
    3 years ago

    How many two dijit numbers are there, which leave remainder 3 on dividing by 8?

  4. Mozahid Mallik
    Mozahid Mallik :
    6 years ago

    Why i take number of terms ,n=13 ? why not any other number of terms?

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