What is the sum of all two digit numbers that gives a remainder of 3 when they are divided by 7?
A. 666
B. 676
C. 683
D. 777
Answer: Option B
A. 666
B. 676
C. 683
D. 777
Answer: Option B
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
676%7 remainder is 4 wrong answer
Mozahid Mallika we are taking n 13 because 7÷(91) is 13 and 3 is reminder
Mozahid Mallika we are taking n 13 because 7÷(91) is 13 and 3 is reminder
How many two dijit numbers are there, which leave remainder 3 on dividing by 8?
Why i take number of terms ,n=13 ? why not any other number of terms?