What is the sum of all two digit numbers that gives a remainder of 3 when they are divided by 7?
A. 666
B. 676
C. 683
D. 777
Answer: Option B
Solution(By Examveda Team)
The two digit number which gives a remainder of 3 when divided by 7 are: 10, 17, 24 ..... 94. Now, these number are in AP series with 1st Term, a = 10; Number of Terms, n = 13; Last term, L = 94 andCommon Difference, d = 7. Sum, $$\eqalign{ & = \left\{ {{\text{n}} \times \frac{{{\text{a}} + {\text{L}}}}{2}} \right\} \cr & = 13 \times 52 \cr & = 676 \cr} $$Join The Discussion
Comments ( 4 )
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
Mozahid Mallika we are taking n 13 because 7÷(91) is 13 and 3 is reminder
Mozahid Mallika we are taking n 13 because 7÷(91) is 13 and 3 is reminder
How many two dijit numbers are there, which leave remainder 3 on dividing by 8?
Why i take number of terms ,n=13 ? why not any other number of terms?