What is the value of $$\frac{{3\sin {{58}^ \circ }}}{{\cos {{32}^ \circ }}} + \frac{{3\sin {{42}^ \circ }}}{{\cos {{48}^ \circ }}}$$
A. 7
B. 9
C. 6
D. 8
Answer: Option C
Solution (By Examveda Team)
$$\eqalign{ & \frac{{3\sin {{58}^ \circ }}}{{\cos {{32}^ \circ }}} + \frac{{3\sin {{42}^ \circ }}}{{\cos {{48}^ \circ }}} \cr & = \frac{{3\cos {{32}^ \circ }}}{{\cos {{32}^ \circ }}} + \frac{{3\cos {{48}^ \circ }}}{{\cos {{48}^ \circ }}} \cr & \left\{ {\therefore \,{{58}^ \circ } + {{32}^ \circ } = {{90}^ \circ }\,\& \,{{42}^ \circ } + {{48}^ \circ } = {{90}^ \circ }} \right\} \cr & = 3 + 3 \cr & = 6 \cr} $$Related Questions on Trigonometry
A. x = -y
B. x > y
C. x = y
D. x < y

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