?
What is the value of $$\frac{{3\sin {{58}^ \circ }}}{{\cos {{32}^ \circ }}} + \frac{{3\sin {{42}^ \circ }}}{{\cos {{48}^ \circ }}}$$
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& \frac{{3\sin {{58}^ \circ }}}{{\cos {{32}^ \circ }}} + \frac{{3\sin {{42}^ \circ }}}{{\cos {{48}^ \circ }}} \cr
& = \frac{{3\cos {{32}^ \circ }}}{{\cos {{32}^ \circ }}} + \frac{{3\cos {{48}^ \circ }}}{{\cos {{48}^ \circ }}} \cr
& \left\{ {\therefore \,{{58}^ \circ } + {{32}^ \circ } = {{90}^ \circ }\,\& \,{{42}^ \circ } + {{48}^ \circ } = {{90}^ \circ }} \right\} \cr
& = 3 + 3 \cr
& = 6 \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login