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What is the value of $$\frac{{\sin \left( {A + B} \right)}}{{\sin A\cos B}}?$$
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& \frac{{\sin \left( {A + B} \right)}}{{\sin A.\cos B}} \cr
& = \frac{{\sin A.\cos B + \cos A.\sin B}}{{\sin A.\cos B}} \cr
& = 1 + \frac{{\cos A.\sin B}}{{\sin A.\cos B}} \cr
& = 1 + \cot A.\tan B \cr} $$
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