What must be added to each term of the ratio 7 : 11, So as to make it equal to 3 : 4?
A. 8
B. 7.5
C. 6.5
D. 5
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & {\text{Let }}x{\text{ be added to each term}}. \cr & {\text{According to question}}, \cr & \frac{{ {7 + x} }}{{11 + x}} = \frac{3}{4} \cr & Or,\,33 + 3x = 28 + 4x \cr & Or,\,x = 5 \cr} $$This Question Belongs to Arithmetic Ability >> Ratio
Why did not assume the first ratio as 7x,11x and added by a constant K.
7x + K ÷ 11x + K = 3 ÷ 4.
Its correct
WHAT WILL BE THE ANSWER??? kindly need a detailed answer for this question..
yes this would be 5. But in mcq, right option is given as 6.5. Hope Admin will correct this.