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What must be added to each term of the ratio 7 : 11, So as to make it equal to 3 : 4?

A. 8

B. 7.5

C. 6.5

D. 5

Answer: Option D

Solution(By Examveda Team)

$$\eqalign{ & {\text{Let }}x{\text{ be added to each term}}. \cr & {\text{According to question}}, \cr & \frac{{ {7 + x} }}{{11 + x}} = \frac{3}{4} \cr & Or,\,33 + 3x = 28 + 4x \cr & Or,\,x = 5 \cr} $$

This Question Belongs to Arithmetic Ability >> Ratio

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Comments ( 4 )

  1. Murali Krishna
    Murali Krishna :
    2 years ago

    Why did not assume the first ratio as 7x,11x and added by a constant K.
    7x + K ÷ 11x + K = 3 ÷ 4.

  2. Humsafar
    Humsafar :
    3 years ago

    Its correct

  3. Priya
    Priya :
    9 years ago

    WHAT WILL BE THE ANSWER??? kindly need a detailed answer for this question..

  4. Rajib Bhattacharyya
    Rajib Bhattacharyya :
    9 years ago

    yes this would be 5. But in mcq, right option is given as 6.5. Hope Admin will correct this.

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