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What must be added to each term of the ratio 7 : 11, So as to make it equal to 3 : 4?
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& {\text{Let }}x{\text{ be added to each term}}. \cr
& {\text{According to question}}, \cr
& \frac{{ {7 + x} }}{{11 + x}} = \frac{3}{4} \cr
& Or,\,33 + 3x = 28 + 4x \cr
& Or,\,x = 5 \cr} $$
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Login7x + K ÷ 11x + K = 3 ÷ 4.