What will be the output of the following C code?
#include<stdio.h>
main()
{
int n,i;
n=f(6);
printf("%d",n);
}
f(int x)
{
if(x==2)
return 2;
else
{
printf("+");
f(x-1);
}
}
#include<stdio.h>
main()
{
int n,i;
n=f(6);
printf("%d",n);
}
f(int x)
{
if(x==2)
return 2;
else
{
printf("+");
f(x-1);
}
}
A. ++++2
B. +++++2
C. +++++
D. 2
Answer: Option A
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void main()
{
int const *p=5;
printf("%d", ++(*p));
}
A. 6
B. 5
C. Garbage Value
D. Compiler Error
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B. mmmm nnnn aaaa
C. Compiler Error
D. None of These
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Determine Output:
void main()
{
static int var = 5;
printf("%d ", var--);
if(var)
main();
}
A. 5 5 5 5 5
B. 5 4 3 2 1
C. Infinite Loop
D. None of These
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